select c.student_id,c.chinese_name, sum(a.absence) absence_total,sum(a.credit) get_course_total,sum(a.coursecredit) reg_course_total
,(select credit from  sm_grade_credit where grade=11)
from sm_course_student a,sm_courses b,sm_students c
where
a.course_id=b.courseid and a.student_id=c.student_id and a.student_id like '11%'
group by c.student_id,c.chinese_name

相关文章:

  • 2022-12-23
  • 2021-10-07
  • 2022-12-23
  • 2021-12-17
  • 2021-07-07
  • 2022-01-27
  • 2022-01-18
  • 2022-12-23
猜你喜欢
  • 2022-12-23
  • 2022-12-23
  • 2022-01-31
  • 2021-10-06
  • 2021-07-09
  • 2021-12-24
  • 2022-12-23
相关资源
相似解决方案