BackgroundThreadFunction()

{

   Invoke(new ShowMessage(Show), strAccount, e.Message);

}

 

private delegate void ShowMessage(string strAccount, string Exception);

private void Show(string strAccount, string Exception)
        {
            lblInfo.Text = "获取" + strAccount;
            lblException.Text =strAccount +  " " + Exception;
        }

相关文章:

  • 2021-08-08
  • 2021-09-17
  • 2022-12-23
  • 2021-12-23
  • 2022-03-09
  • 2022-12-23
  • 2021-12-20
猜你喜欢
  • 2021-11-25
  • 2022-12-23
  • 2022-12-23
  • 2021-06-27
  • 2021-12-23
  • 2021-12-23
  • 2021-10-27
相关资源
相似解决方案