If we list all the natural numbers below 10 that are multiples of 3 or 5, we get 3, 5, 6 and 9.
The sum of these multiples is 23.
Find the sum of all the multiples of 3 or 5 below 1000.
long result = 0;
for (int i = 0; i < 1000; i++)
{
if (i%3 == 0 || i%5 == 0) result += i;
}
Console.WriteLine(result);