SELECT o.[name], o.[type], i.[name], i.[index_id], f.[name]
FROM sys.indexes i
INNER JOIN sys.filegroups f
ON i.data_space_id = f.data_space_id
INNER JOIN sys.all_objects o
ON i.[object_id] = o.[object_id]
WHERE f.name = 'primary'

 

相关文章:

  • 2022-12-23
  • 2022-12-23
  • 2021-10-03
  • 2021-11-17
  • 2021-11-29
  • 2022-12-23
  • 2022-03-01
  • 2022-12-23
猜你喜欢
  • 2022-03-11
  • 2022-12-23
  • 2021-10-22
  • 2021-12-29
  • 2022-12-23
  • 2022-12-23
  • 2021-07-24
相关资源
相似解决方案