import re

pattern = re.compile(r'\d+')
s = pattern.search('hello 123456 789')
print(s.group())

s = pattern.findall('hello 13456 789')
print(s)



# str = 'I love You!'
# def daoxuprint(str):
#     i = len(str)-1
#     while i >= 0:
#         print(str[i],end='')
#         i -= 1
# #方法二
# pattern = re.compile(r'.')
# s = pattern.findall(str)
# print(s)
# for item in s:
#     # print(item)
#     daoxuprint('love')


#举例2 I love You
# pattern = re.compile(r'(\w+)(!?)')
# s = pattern.findall(str)
# print(s,type(s))
# for item in s:
#     for i in item:
#         if i == '':
#             daoxuprint(' ')
#         else:
#             daoxuprint(i)
# #\. 是刚需必须有  d+ 必须一个或多个数字
# pattern = re.compile(r'\d+\.\d*')
#
# d = pattern.findall('3.141592653 PI 100 10001.11 3. .8 0.9')
# print(d)

 

相关文章:

  • 2021-09-22
  • 2022-01-22
  • 2022-02-16
  • 2022-02-03
  • 2021-07-28
  • 2022-12-23
猜你喜欢
  • 2022-01-14
  • 2022-02-14
  • 2022-01-14
  • 2022-12-23
  • 2022-01-08
  • 2021-11-03
  • 2021-09-05
相关资源
相似解决方案