参考:http://www.cnblogs.com/h07061108/p/mysql_questions.html#3806338

实现如下效果

【mysql经典题目】行转列

 

CREATE TABLE IF NOT EXISTS tb_amount(
   `Id` INT NOT NULL AUTO_INCREMENT,
   `Year` CHAR(4),
   `Month` CHAR(2),
   `Amount` DECIMAL(5,2),
   PRIMARY KEY(`Id`)
);

INSERT INTO `tb_amount`(`Year`, `Month`, `Amount`) VALUES('1991', '1', '1.1');
INSERT INTO `tb_amount`(`Year`, `Month`, `Amount`) VALUES('1991', '2', '1.2');
INSERT INTO `tb_amount`(`Year`, `Month`, `Amount`) VALUES('1991', '3', '1.3');
INSERT INTO `tb_amount`(`Year`, `Month`, `Amount`) VALUES('1991', '4', '1.4');
INSERT INTO `tb_amount`(`Year`, `Month`, `Amount`) VALUES('1992', '1', '2.1');
INSERT INTO `tb_amount`(`Year`, `Month`, `Amount`) VALUES('1992', '2', '2.2');
INSERT INTO `tb_amount`(`Year`, `Month`, `Amount`) VALUES('1992', '3', '2.3');
INSERT INTO `tb_amount`(`Year`, `Month`, `Amount`) VALUES('1992', '4', '2.4');

SELECT `Year`,
(SELECT Amount FROM   tb_amount m WHERE `Month`=1   AND m.`Year`=tb_amount.`Year`) AS m1,
(SELECT Amount FROM   tb_amount m WHERE `Month`=2   AND m.`Year`=tb_amount.`Year`) AS m2,
(SELECT Amount FROM   tb_amount m WHERE `Month`=3   AND m.`Year`=tb_amount.`Year`) AS m3,
(SELECT Amount FROM   tb_amount m WHERE `Month`=4   AND m.`Year`=tb_amount.`Year`) AS m4
FROM tb_amount  GROUP BY `Year`;

或者

select year,
max(case month when 1 then amount else 0 end ) m1,
max(case month when 2 then amount else 0 end) m2,
max(case month when 3 then amount else 0 end) m3,
max(case month when 4 then amount else 0 end) m4
from tb_amount
group by year;

 




 

相关文章:

  • 2022-03-04
  • 2021-11-17
  • 2021-08-22
  • 2021-06-13
  • 2022-12-23
  • 2021-05-19
猜你喜欢
  • 2022-12-23
  • 2021-05-10
  • 2022-01-07
  • 2022-01-07
  • 2021-11-04
  • 2022-01-15
  • 2021-09-02
相关资源
相似解决方案