SQL Server利用XML找字符串相同部分

DECLARE @a NVARCHAR(100)= '01,02,04,05,07';
DECLARE @b NVARCHAR(100)= '01,03,04,05,06';
WITH    a1
          AS ( SELECT   CONVERT(XML, '<root><v>' + REPLACE(@a, ',', '</v><v>')
                        + '</v></root>') cxml
             ),
        a AS ( SELECT   v.value('.', 'varchar(100)') cv
               FROM     a1
                        CROSS APPLY cxml.nodes('/root/v') AS C ( v )
             ),
        b1
          AS ( SELECT   CONVERT(XML, '<root><v>' + REPLACE(@b, ',', '</v><v>')
                        + '</v></root>') cxml
             ),
        b AS ( SELECT   v.value('.', 'varchar(100)') cv
               FROM     b1
                        CROSS APPLY cxml.nodes('/root/v') AS C ( v )
             ),
        x1
          AS ( SELECT   1 AS z ,
                        a.cv
               FROM     a
                        JOIN b ON a.cv = b.cv
             ),
        x0
          AS ( SELECT   z ,
                        ( SELECT    cv + ','
                          FROM      x1
                          WHERE     z = t1.z
                          ORDER BY  z
                        FOR
                          XML PATH('')
                        ) AS l
               FROM     x1 t1
               GROUP BY z
             )
    SELECT  LEFT(l, LEN(l) - 1) AS vs
    FROM    x0;

vs
---------------------------------------------
01,04,05

(1 行受影响)