Given two non-empty binary trees s and t, check whether tree t has exactly the same structure and node values with a subtree of s. A subtree of s is a tree consists of a node in s and all of this node's descendants. The tree s could also be considered as a subtree of itself.

Example 1:
Given tree s:

     3
    / \
   4   5
  / \
 1   2
Given tree t:
   4 
  / \
 1   2
Return true, because t has the same structure and node values with a subtree of s.

 

Example 2:
Given tree s:

     3
    / \
   4   5
  / \
 1   2
    /
   0
Given tree t:
   4
  / \
 1   2
Return false.
 
  思路: 
1  写一个判断树是否相同的函数
2 递归的判断当前树节点是否相同。
 
 1 class Solution {
 2     public boolean isSubtree(TreeNode s, TreeNode t) {
 3         if(s == null) return false;
 4         if(isSame(s,t)) return true;
 5         return isSubtree(s.left,t) || isSubtree(s.right,t);
 6     }
 7     public boolean isSame(TreeNode s, TreeNode t) {
 8         if(s == null && t == null) return true;
 9         if(s == null || t == null) return false;
10         
11         if(s.val != t.val) return false;
12         
13         return isSame(s.left,t.left)  && isSame(s.right,t.right); 
14         
15     }
16 }

 

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