<xsl:template match="/uo_content/attractions/ride"> ...</xsl:template>
How about if we want to get the "template" element from this document?
var template = doc.getElementByTagName("xsl:template")[0] // <--It does work, but only for IE
var template = doc.getElementByTagName("template")[0] // <-- Firefox only
var template = doc.getElementByTagName("xsl:template")[0] || doc.getElementByTagName("template")[0] //<-- Both
Consider that "xsl" is a namespace but not a part of the tag name, I think Firefox way is better.(Tested in IE6 and FF2)