mysql每日一题- 部分top3工资查询

solution

SELECT
	a.employee,
	a.department,
	a.Salary 
FROM
	(
	SELECT
		*,
		DENSE_RANK() over ( PARTITION BY department ORDER BY Salary DESC ) rk 
	FROM
		( SELECT a.NAMES employee, b.NAME department, Salary FROM T0917 a INNER JOIN t0917b b ON a.DepartmentID = b.id ) a 
	) a 
WHERE
	a.rk IN ( 1, 2, 3 )