python面试，日更

l1 = [11, 2, 3, 22, 2, 4, 11, 3]
去重并保持原来顺序

# 集合方法
l2 = list(set(l1))
l2.sort(key=l1.index) # 按照l1索引排序
print(l2)

# 列表
l3 = []
for item in l1:
    if item not in l3:
        l3.append(item)
print(l3)

答案