Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)
Total Submission(s): 2084    Accepted Submission(s): 1348


Problem Description
Connecting the display screen and signal sources which produce different color signals by cables, then the display screen can show the color of the signal source.Notice that every signal source can only send signals to one display screen each time. 
Now you have  display screens and  different signal sources(). Select  display screens from  display screens, how many cables are needed at least so that **any**  display screens you select can show exactly  different colors.
 

Input
Multiple cases (no more than ), for each test case:
there is one line contains two integers .
 

Output
Output the minimum number of cables .
 

Sample Input

3 2 20 15
 

Sample Output

4 90
Hint
hdu6195 cable cable cable
As the picture is shown, when you select M1 and M2, M1 show the color of K1, and M2 show the color of K2. When you select M3 and M2, M2 show the color of K1 and M3 show the color of K2. When you select M1 and M3, M1 show the color of K1.
 

Statistic | Submit | Clarifications | Back


题意:给出m个显示屏和k个信号,要求任选k个显示屏都可以显示所有的信号

思路:找规律

#include <iostream>

using namespace std;
typedef long long ll;
int main()
{
   ll m,k;
   while(cin>>m>>k)
   {


   ll tmp=m-(k+1);
   cout<<k*2+tmp*k<<endl;
   }
    return 0;
}



相关文章: