hdu 1242 找到朋友最短的时间 (BFS+优先队列)

找到朋友的最短时间

Sample Input
7 8
#.#####. //#不能走 a起点 x守卫 r朋友
#.a#..r. //r可能不止一个
#..#x...
..#..#.#
#...##..
.#......
........

Sample Output
13

bfs+优先队列

 1 #include <iostream>
 2 #include <cstring>
 3 #include <cstdio>
 4 #include <queue>
 5 using namespace std;
 6 
 7 int n, m;
 8 char map[205][205];
 9 int sx, sy;
10 bool flag;
11 
12 struct node
13 {
14     int x , y , step ;
15     bool operator <(const node &t) const
16     {
17         return step > t.step ;
18     }
19 };
20 
21 int dx[] = {0,0,1,-1} ;
22 int dy[] = {1,-1,0,0} ;
23 
24 void bfs()
25 {
26     node now , t ;
27     int i , fx ,fy ;
28     priority_queue<node> q ;
29     now.x = sx ;
30     now.y = sy ;
31     now.step = 0 ;
32     q.push(now) ;
33     map[sx][sy] = '#' ;
34     while(!q.empty())
35     {
36         now = q.top() ;
37         q.pop() ;
38         for (i = 0 ; i < 4 ; i++)
39         {
40             fx = now.x + dx[i] ;
41             fy = now.y + dy[i] ;
42             if (fx<0 || fy<0 || fx >=n || fy >=m ||map[fx][fy] == '#')
43                 continue ;
44             if (map[fx][fy] == 'r')
45             {
46                 printf("%d\n" , now.step+1) ;
47                 flag = 1 ;
48                 return ;
49             }
50             if (map[fx][fy] == 'x')
51             {
52                 t.x = fx ;
53                 t.y = fy ;
54                 t.step = now.step + 2 ;
55                 q.push(t) ;
56             }
57             else
58             {
59                 t.x = fx ;
60                 t.y = fy ;
61                 t.step = now.step + 1 ;
62                 q.push(t) ;
63             }
64             map[fx][fy] = '#' ;
65 
66         }
67     }
68 
69 
70 }
71 
72 int main()
73 {
74   //  freopen("in.txt","r",stdin) ;
75     while (scanf("%d %d" , &n , &m) !=EOF)
76     {
77         int i , j ;
78         for (i = 0 ; i < n ; i++)
79         {
80             for (j = 0 ; j < m ; j++)
81             {
82                 cin>>map[i][j] ;
83                 if (map[i][j] == 'a')
84                 {
85                     sx = i ;
86                     sy = j ;
87                 }
88             }
89         }
90         flag = 0 ;
91         bfs() ;
92         if (!flag)
93             printf("Poor ANGEL has to stay in the prison all his life.\n") ;
94     }
95 
96     return 0 ;
97 }

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