url跳转路径参数获取

function getUrlParam1(name){
    //正则表达式过滤
    var reg = new RegExp("(^|&)" + name + "=([^&]*)(&|$)", "i");
    var r = window.location.search.substr(1).match(reg);
    if (r != null) return decodeURI(r[2]); return null;

}