Valid Anagram

Given two strings s and t, write a function to determine if t is an anagram of s.

For example,
s = "anagram", t = "nagaram", return true.
s = "rat", t = "car", return false.

Note:
You may assume the string contains only lowercase alphabets.

 

解法一:排序后判相等

class Solution {
public:
    bool isAnagram(string s, string t) {
        sort(s.begin(), s.end());
        sort(t.begin(), t.end());
        return s == t;
    }
};

【LeetCode】242. Valid Anagram (2 solutions)

 

解法二:计数判相等

class Solution {
public:
    bool isAnagram(string s, string t) {
        vector<int> count(26, 0);
        for(int i = 0; i < s.size(); i ++)
            count[s[i]-'a'] ++;
        for(int i = 0; i < t.size(); i ++)
            count[t[i]-'a'] --;
        for(int i = 0; i < 26; i ++)
            if(count[i] != 0)
                return false;
        return true;
    }
};

【LeetCode】242. Valid Anagram (2 solutions)

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