只要不能写成\(2^N N \subseteq N^*\)就肯定有
#include<iostream>
#include<cstdio>
#include<cmath>
#define int long long
using namespace std;
int n,m;
int prime[5000001];
int flag[10000001];
int Aimee[5000001];
int p;
int num;
int now;
int t;
long long x;
signed main(){
scanf("%d",&t);
while(t--){
int f=0;
scanf("%lld",&x);
while(x>1){
if(x&1){
cout<<"Yes\n";
f=1;
break;
}
x>>=1;
}
if(!f){
cout<<"No\n";
}
}
return 0;
}