.... //for(its=StopWordL.begin();its!=StopWordL.end();its++){ //if(TermToDic.compare(*its)==0) { // cout<<"## stop word"<<*its<<endl; //return false; // }//is a stop word // else return true; //acout<<"test for TermToDic"<<TermToDic<<endl; //cout<<"test for StopWord:"<<*its<<endl; its=find(StopWordL.begin(),StopWordL.end(),TermToDic); 这里自己些的那种查找某字段存在的方法好像行不通,改用没注释的倒是可以了! 相关文章: 2021-11-18 2021-10-27 2021-10-09 2022-03-06 2021-07-15 2022-01-12 2022-02-27 2021-11-29