因为不是一队……毫无晋级的压力……反正有压力也进不去呵呵呵……

开场zr看1006我看1010。。

1010我一直在wa。。。

zr的1006倒是比较轻松的过了。。。然后我让他帮我看10。。。。

跟他讲了半天我代码的逻辑。。。然后我自己看出来的。。。。比赛的代码。。。。写的十分混乱。。。。

#include <cstdio>
#include <cstring>
#include <algorithm>
#include <vector>
typedef long long ll;
using namespace std;
const int N = 100005;
vector<int> G[N];

int a[N], b[N];
int low[N];
int par[N];
int c[N];
int cntv;
ll ans;
int n;

int lowbit(int x)
{
    return x & (-x);
}

int sum(int n)                //前n个数的和
{
    int ans = 0;
    while (n > 0) {
        ans +=  c[n];
        n -= lowbit(n);
    }
    return ans;
}

void add(int pos, int num, int n)    //在pos处加num
{
    while (pos <= n) { 
        c[pos] += num;
        pos += lowbit(pos);
    }
}

void dfs(int u) {
    //printf("==%d %d %d\n", u, a[u], low[ a[u] ]);
    //printf("n = %d\n", n);
    int lowu = low[ a[u] ];
    int tmp = sum(lowu);
    for (unsigned i = 0; i < G[u].size(); ++i) {
        int v = G[u][i];
        dfs(v);
    }
    int tmp2 = sum(lowu);
    add(a[u], 1, n);
    cntv++;
    //printf(">>%d %d %d\n", u, tmp, tmp2);
    ans += tmp2 - tmp;
}

void init() {
    memset(c, 0, sizeof c);
    memset(low, 0, sizeof low);
    memset(par, 0, sizeof par);
}

int main()
{
    //freopen("in.txt", "r", stdin);
    int T;
    scanf("%d", &T);
    while (T--) {
        ll k;
        init();
        scanf("%d%lld", &n, &k);
        //printf("%d %lld\n", n, k);
        for (int i = 1; i <= n; ++i) {
            G[i].clear();
            scanf("%d", &a[i]);
            b[i] = a[i];
        }
        sort(b+1, b+1+n);
        int cnt = unique(b+1, b+1+n) - (b+1);
        //printf("cnt=%d\n",cnt);
        //for (int i = 1; i <= cnt; ++i) printf("|%d ", b[i]); printf("\n");
        int idx = cnt;
        for (int i = 1; i <= cnt; ++i) {
            while ((ll)b[i]*b[idx--] > k) ;
            idx++; low[i] = idx;
        }//low[i]记录的是i*low[i]<=k的最大值
        //for (int i = 1; i <= n; ++i) printf("%d ", low[i]); printf("\n");
        for (int i = 1; i <= n; ++i) {
            a[i] = lower_bound(b+1, b+1+cnt, a[i]) - b;
        }
        //for (int i = 1; i <= n; ++i) { printf("%d %d\n", a[i], low[ a[i] ]); }

        int u, v;
        for (int i = 1; i < n; ++i) {//printf("i=%d\n", i);
            scanf("%d%d", &u, &v);
            G[u].push_back(v);
            par[v] = u;
        }
        int root = 1;
        while (par[root]) root = par[root];
        //printf("root=%d\n", root);
        cntv = 0;
        ans = 0;
        dfs(root);
        printf("%lld\n", ans);
    }
    return 0;
}
View Code

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