LeetCode: Find Peak Element 解题报告

 

A peak element is an element that is greater than its neighbors.

Given an input array where num[i] ≠ num[i+1], find a peak element and return its index.

The array may contain multiple peaks, in that case return the index to any one of the peaks is fine.

You may imagine that num[-1] = num[n] = -∞.

For example, in array [1, 2, 3, 1], 3 is a peak element and your function should return the index number 2.

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Credits:
Special thanks to @ts for adding this problem and creating all test cases.

SOLUTION 1:

线性查找，时间O(N):

 1 public int findPeakElement1(int[] num) {
 2         if (num == null) {
 3             return 0;
 4         }
 5         
 6         if (num.length == 1) {
 7             return 0;
 8         }
 9         
10         for (int i = 0; i < num.length; i++) {
11             if (i == 0) {
12                 if (num[i] > num[i + 1]) {
13                     return i;
14                 }
15                 continue;
16             }
17             
18             if (i == num.length - 1) {
19                 if (num[i] > num[i - 1]) {
20                     return i;
21                 }
22                 continue;
23             }
24             
25             if (num[i] > num[i + 1] && num[i] > num[i - 1]) {
26                 return i;
27             }
28         }
29         
30         return -1;
31     }

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