对成绩排序,相同的为同名次。。。
另一种方法:
select s1.score,(select count(distinct s2.score) from score as s2 where s2.score>=s1.score) as rank
from score as s1 order by s1.score desc;
对成绩排序,相同的为同名次。。。
另一种方法:
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