有两个列表A,B

A = [[[3, 5], [0, 2], [2, 10]], [[6, 9], [7, 2], [9, 7]], [[3, 3], [5, 3], [10, 2]]];

B = [[0, 2], [2, 10], [3, 3]]; 

如何得到[[0, 1, 1], [0, 0, 0], [1, 0, 0]]?

求解:

>>> A = [[[3, 5], [0, 2], [2, 10]], [[6, 9], [7, 2], [9, 7]], [[3, 3], [5, 3], [10, 2]]]
>>> B = [[0, 2], [2, 10], [3, 3]]
>>> C = [[B.count(x) for x in y] for y in A]
>>> C
[[0, 1, 1], [0, 0, 0], [1, 0, 0]]

 

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