2019CCPC秦皇岛D题 Decimal

Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 131072/131072 K (Java/Others)
Total Submission(s): 103    Accepted Submission(s): 49

Problem Description

Given a positive integer n, determine if n is an infinite decimal in decimal base. If the answer is yes, print “Yes” in a single line, or print “No” if the answer is no.

 

 

Input

The first line contains one positive integer T (1 ≤ T ≤ 100), denoting the number of test cases.
For each test case:
Input a single line containing a positive integer n (1 ≤ n ≤ 100).

 

 

Output

Output T lines each contains a string “Yes” or “No”, denoting the answer to corresponding test case.

 

 

Sample Input

2 5 3

 

 

Sample Output

No Yes

Hint

1/5 = 0.2, which is a finite decimal. 1/3 = 0.333 · · · , which is an infinite decimal.

 

 

Source

642ccpcQHD

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题解：

问1/n是否是有限小数，队友很快反应过来找n是否含有非2和非5的因子。

参考代码：

 

#include<bits/stdc++.h>
using namespace std;
int main()
{
    int t;
    scanf("%d",&t);
    while(t--)
    {
        int n;
        scanf("%d",&n);
        if(n%5==0)
        {
            do{
                n/=5;
            }while(n%5==0);
        }
        if(n%2==0)
        {
            do{n/=2;}while(n%2==0);
        }
        if(n==1) puts("No");
        else puts("Yes");
    }
    return 0; 
}

View Code