2024-C语言合法标识符

Problem Description

输入一个字符串，判断其是否是C的合法标识符。

 

 

Input

输入数据包含多个测试实例，数据的第一行是一个整数n,表示测试实例的个数，然后是n行输入数据，每行是一个长度不超过50的字符串。

 

 

Output

对于每组输入数据，输出一行。如果输入数据是C的合法标识符，则输出"yes"，否则，输出“no”。

 

 

Sample Input

3 12ajf fi8x_a ff ai_2

 

 

Sample Output

no yes no

 

AC代码：

 

#include<stdio.h>
#include<string.h>
void main()
{
    int n=0,i,j,k,s,x,y,z;
    char a[55];
    char b[33][10]={"auto","break","case","char","const","continue","default","do","double","else","enum","extern","float","for","goto","if","int","long","register","return","short","signed","sizeof","static","struct","switch","typedef","union","unsigned","void","volatile","while"};
    scanf("%d",&n);
    getchar();
    for(i=1;i<=n;i++)
    {
        gets(a);
        s=strlen(a);
        x=y=z=1;
        if(a[0]==\'_\'||(a[0]>=\'A\'&&a[0]<=\'Z\')||(a[0]>=\'a\'&&a[0]<=\'z\'))
        {
            x=0;
            for(j=0;j<32;j++)
                if(!strcmp(a,b[j]))
                    z=0;
            for(j=1;j<s;j++)
            {
                if(a[j]==\'_\'||(a[j]>=\'A\'&&a[j]<=\'Z\')||(a[j]>=\'a\'&&a[j]<=\'z\')||(a[j]>=\'0\'&&a[j]<=\'9\'))
                    continue;

                else y=0;
            }
        }
    //    printf("%d%d%d",x,y,z);
        if(x==0&&y==1&&z==1)
            printf("yes\n");
        else printf("no\n");
    }
}