leetcode-python 在一个长字符串中寻找子字符串的出现次数以及位置

code

S = 'xxxabcxxxxabcxxabcxxabc'
search="xxxa"
last_cur=0
count=0


while(1):
    where=S.find(search)
    if(not where==-1):
        print(last_cur+where)
        S=S[where+len(search):]
        last_cur=last_cur+where+len(search)
        count+=1
    else:
        break
    
print("总数为：",count)