Suppose an array sorted in ascending order is rotated at some pivot unknown to you beforehand.
(i.e., [0,0,1,2,2,5,6] might become [2,5,6,0,0,1,2]).
You are given a target value to search. If found in the array return true, otherwise return false.
Example 1:
Input: nums = [2,5,6,0,0,1,2], target = 0
Output: true
Example 2:
Input: nums = [2,5,6,0,0,1,2], target = 3
Output: false
Follow up:
- This is a follow up problem to Search in Rotated Sorted Array, where
numsmay contain duplicates. - Would this affect the run-time complexity? How and why?
这道是之前那道 Search in Rotated Sorted Array 中的方法，可以得到代码如下：
class Solution { public: bool search(vector<int>& nums, int target) { int n = nums.size(), left = 0, right = n - 1; while (left <= right) { int mid = (left + right) / 2; if (nums[mid] == target) return true; if (nums[mid] < nums[right]) { if (nums[mid] < target && nums[right] >= target) left = mid + 1; else right = mid - 1; } else if (nums[mid] > nums[right]){ if (nums[left] <= target && nums[mid] > target) right = mid - 1; else left = mid + 1; } else --right; } return false; } };
Github 同步地址：
https://github.com/grandyang/leetcode/issues/81
类似题目：
Search in Rotated Sorted Array
参考资料：
https://leetcode.com/problems/search-in-rotated-sorted-array-ii/
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