使用SAX解析XML实例--根据属性查找

XML:

目的：输入sn=01 把相应的student的肮name和age取回

<?xml version="1.0" encoding="UTF-8"?>
<?xml-stylesheet type="text/xsl" href="student.xsl"?>
<students>
  <student sn="01">
    <name>gao</name>
    <age>27</age>
  </student>
  <student sn="02">
    <name>yu</name>
    <age>24</age>
  </student>
</students>

 

package sax;

import java.io.File;
import java.io.IOException;
import java.util.Stack;

import javax.xml.parsers.ParserConfigurationException;
import javax.xml.parsers.SAXParser;
import javax.xml.parsers.SAXParserFactory;

import org.xml.sax.Attributes;
import org.xml.sax.SAXException;
import org.xml.sax.helpers.DefaultHandler;

 

用异常完成查找，结果如下：

name: gao
age: 27
org.xml.sax.SAXException: 找到了匹配的学生
 at sax.StudentLookup.endElement(StudentLookup.java:84)
 at org.apache.xerces.parsers.AbstractSAXParser.endElement(Unknown Source)
 at org.apache.xerces.impl.XMLDocumentFragmentScannerImpl.scanEndElement(Unknown Source)
 at org.apache.xerces.impl.XMLDocumentFragmentScannerImpl$FragmentContentDispatcher.dispatch(Unknown Source)
 at org.apache.xerces.impl.XMLDocumentFragmentScannerImpl.scanDocument(Unknown Source)
 at org.apache.xerces.parsers.XML11Configuration.parse(Unknown Source)
 at org.apache.xerces.parsers.XML11Configuration.parse(Unknown Source)
 at org.apache.xerces.parsers.XMLParser.parse(Unknown Source)
 at org.apache.xerces.parsers.AbstractSAXParser.parse(Unknown Source)
 at javax.xml.parsers.SAXParser.parse(SAXParser.java:375)
 at javax.xml.parsers.SAXParser.parse(SAXParser.java:311)
 at sax.StudentLookup.main(StudentLookup.java:148)

如果不想打印出异常堆栈，则只要屏蔽掉
catch (SAXException e) {
   e.printStackTrace();
}