mysql中in 做条件匹配 带逗号的字符串 数据异常解决

 

在数据库中表doctor中cancer字段存放着以逗号分隔的外键id

select cancer from doctor where id=1;  

 

数据如下：

cancer

1,2,3

我需要在表cancer_type中匹配刚刚的外键,
于是用FIND_IN_SET函数:

select * from cancer_type c where FIND_IN_SET(c.cancer_id, (select cancer from doctor where id=1) )  

数据如下：

cancer_id	cancer_name	cancer_prefix
1	肺癌	Lung
2	结直肠癌	Col
3	胃癌	Sto

用in来匹配却不行

select * from cancer_type where cancer_id in (select cancer from doctor where id=1)  

数据如下:

cancer_id	cancer_name	cancer_prefix
1	肺癌	Lung

 

https://www.iteye.com/blog/fengjianrong-2218577