char & operator[](int i);
const char & operator[](int i);/*const char & operator(int i);*/
编译出错:
error C2556: 'const char &MyString::operator [](int)' : overloaded function differs only by return type from 'char &MyString::operator [](int)'
修改:
char & operator[](int i);
const char & operator[](int i) const;/*const char & operator(int i);*/
就可以了。

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