C. News Distribution(并查集)

In some social network, there are m groups of friends. Let's analyze the process of distributing some news between users.

Initially, some user x receives the news from some source. Then he or she sends the news to his or her friends (two users are friends if there is at least one group such that both of them belong to this group). Friends continue sending the news to their friends, and so on. The process ends when there is no pair of friends such that one of them knows the news, and another one doesn't know.

For each user x starts distributing it.

Input

The first line contains two integers 1≤n,m≤5⋅105) — the number of users and the number of groups of friends, respectively.

Then i-th group.

It is guaranteed that ∑i=1mki≤5⋅105.

Output

Print i starts distributing it.

Example

input

Copy

7 5
3 2 5 4
0
2 1 2
1 1
2 6 7

output

Copy

4 4 1 4 4 2 2 

 

 代码：

#include<cstdio>
#include<cstring>
#include<iostream>
#include<algorithm>
#include<queue>
#include<stack>
#include<set>
#include<vector>
#include<map>
#include<cmath>

const int maxn=5e5+5;
typedef long long ll;
using namespace std;
int pre[maxn];
int find(int x)
{
    if(x==pre[x])
    {
        return x;
    }
    else
    {
        return pre[x]=find(pre[x]);
    }
}
void Merge(int x,int y)
{
    int xx=find(x);
    int yy=find(y);
    if(xx!=yy)
    {
        pre[xx]=yy;
    }
    
}
int a[maxn];
int main()
{
    int n,m;
    cin>>n>>m;
    int x;
    for(int t=1;t<=n;t++)
    {
        pre[t]=t;
    }
    int s1,s2;
    for(int t=0;t<m;t++)
    {
        scanf("%d",&x);
        if(x!=0)
        scanf("%d",&s1);
        for(int j=1;j<x;j++)
        {
            scanf("%d",&s2);
            Merge(s1,s2);
            s1=s2;
        }
    }

    int ans=0;
    memset(a,0,sizeof(a));
    for(int t=1;t<=n;t++)
    {
    
        a[find(t)]++;
    }
    for(int t=1;t<=n;t++)
    {
        printf("%d ",a[find(t)]);
    }

    
    return 0;
}