panpy

#递归实现
def calc(n):
  print(n)
  if n/2 >1:
    res = calc(n/2)
    print(\'res:\',res)
  print(\'N:\',n)
  return n

  calc(100)

#斐波那契数列
def func(arg1,arg2,stop)
  if arg1 == 0:
    print(arg1,arg2)
  arg3 = arg1 + arg2
  print(arg3)
  if arg3 < stop:
    func(arg2,arg3,stop)

func(0,1,30)

#算法基础之二分查找
def binary_search(data_source,find_n):
  mid = int(len(data_source)/2)
  if len(data_source) > 1:
    if data_source[mid] > find_n:
    print("data in left of [%s]" % data_source[mid])
    binary_search(data_source[:mid],find_n)
    elif data_source[mid] < find_n:
      print("data in right of [%s]" % data_source[mid])
      binary_search(data_source[mid:],find_n)
    else
      print("found find_s",data_source[mid])
  else:
    print("connot find....")

if __name__ == \'__main__\':
  data = list(range(1,6000000))
  binary_search(data,65535)

分类:

技术点:

相关文章:

  • 2021-08-05
  • 2021-09-07
  • 2022-01-12
  • 2021-05-19
  • 2021-07-22
  • 2021-09-20
  • 2021-12-10
  • 2021-10-10
猜你喜欢
  • 2021-09-07
  • 2021-09-07
  • 2021-09-07
  • 2021-10-08
  • 2021-05-06
  • 2021-05-27
  • 2021-07-19
相关资源
相似解决方案