Wendy7735

jqGrid复制表格数据到另外一张表中

var selectedIds = $("#jqGrid_chooseProjectPerson").jqGrid("getGridParam", "selarrrow");
var old_ids = $(\'#jqGrid_alreadyChoose\').getDataIDs();//目标表中所有数据的行号
for (var i = 0; i < selectedIds.length; i++) {
var j = old_ids.indexOf(selectedIds[i]);
if (j == -1) {
var rowData = $("#jqGrid_chooseProjectPerson").jqGrid(\'getRowData\', selectedIds[i]);
$(\'#jqGrid_alreadyChoose\').jqGrid("addRowData", selectedIds[i], rowData);
$("#jqGrid_alreadyChoose").jqGrid(\'setSelection\',selectedIds[i]);
}
}
发表于 2018-08-09 15:30  WendyQQ35  阅读(466)  评论(0编辑  收藏  举报
 

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