昨天发了一个无水印解析，评论说想要多线程下载，还是比较简单的。 py文件同目录下创建url.txt，把链接一行一行复制进去，就能批量下载。
代码中的延时不能去掉，由于是多线程，速度较快，延时很重要。
import re
import requests
from concurrent import futures
import time
headers = {\'user-agent\': \'Mozilla/5.0 (Windows NT 10.0; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/72.0.3626.96 Safari/537.36\'}
def download(_url):
try:
time.sleep(0.3)
html3 = requests.head(_url,headers = headers)
download_url = html3.headers[\'Location\']
video_file = requests.get(download_url,headers = headers)
file_name = download_url.split(\'=\')[-1]
print(file_name)
except:
print(\'Error\')
with open(file_name + \'.mp4\',\'wb\') as code:
code.write(video_file.content)
def main():
data_file = open(\'url.txt\')
data_url = data_file.read()
data_url_list1 = data_url.split(\'\n\')
Threads = futures.ThreadPoolExecutor(min(Max_workers,len(data_url_list1)))
for x in data_url_list1:
html1 = requests.head(x)
first_url = html1.headers[\'Location\']
html2 = requests.get(first_url,headers = headers)
text_data = html2.text
video_player_url1 = re.findall(\'playAddr: "(.*?)"\',text_data,re.S)[0]
video_player_url2 = video_player_url1.replace(\'wm\',\'\')
#download(video_player_url2)
Threads.submit(download,video_player_url2)
Max_workers = 5
main()