?select GETDATE() as \'当前日期\',
DateName(year,GetDate()) as \'年\',
DateName(month,GetDate()) as \'月\',
DateName(day,GetDate()) as \'日\',
DateName(dw,GetDate()) as \'星期\',
DateName(week,GetDate()) as \'周数\',
DateName(hour,GetDate()) as \'时\',
DateName(minute,GetDate()) as \'分\',
DateName(second,GetDate()) as \'秒\'
结果:
2009-08-13 23:07:15.403 2009 08 13 星期四 33 23 7 15
本文来自CSDN博客:http://blog.csdn.net/ddjiang1115/archive/2010/08/27/5843522.aspx
select getdate()
2012-05-21 16:42:17.373
select datename(year,getdate())
2012