ajax请求后根据条件进行页面跳转 - paul_cheung

ajax请求后根据条件进行页面跳转

　　

　　　　　　　　　　　　$.ajx({
                            url: "@Url.Action("DetectCorporationCompetencyCreated", "DataBase")",
                            data: { corporationId: rowId },
                            async:false,
                            success: function (data) {
                                corporationHasCompetencyCreated = data > 0;
                            },
                            error: function () {
                                alert("检测企业数据库存在能力失败");
                            }
                        });

                        if (corporationHasCompetencyCreated) {
                            window.open("@Url.Action("ConfigCompetency", "CorporationManagement")" + "?corporationId=" + rowId, "_self", "", true);
                        }