formSubmit

精简代码；

<form name=\'form0001\' method="post"> 。。。。

 <li id="view"><a href="#" onclick="formSubmit(\'toview.action\',\'_self\');this.blur();">查看</a></li>
 <li id="new"><a href="#" onclick="formSubmit(\'tocreate.action\',\'_self\');this.blur();">新增</a></li>

<li id="delete"><a href="#" onclick="formSubmit(\'delete.action\',\'_self\');this.blur();">删除N</a></li>

</form>

/* 打开一个新页面 */
function formSubmit (url,sTarget){
    document.forms[\'form0001\'].target = sTarget

    document.forms[0].action = url;
    document.forms[0].submit();
    return true;
}

    //删除多条
    @RequestMapping("/delete.action")
    public String delete(@RequestParam("id") String[] ids) {
        System.out.println(ids);
//        fyService.delete(ids);

        return "redirect:/list.action";
    }

this.blur()：链接聚焦触发时失去焦点，去除链接获取焦点后外围的虚线框