js 将两个数组里的对象一一对应合并

ar obj1 = [{
  "id": 980550455852,
  "model": "XQG70-S1208FW",
  "color": "白",
  "invStatusName": "正品",
  "bactualQty": 10947,
  "brealyQty": 11000,
  "bavailQty": 53
}, {
  "id": 980550566221,
  "model": "XQB70-C3006",
  "color": "灰",
  "invStatusName": "正品",
  "bactualQty": 11,
  "brealyQty": 6,
  "bavailQty": -5
}];

var obj2 = [{
  "price": "6666"
}, {
  "price": "8888"
}];

上面是两个数组里面有对个对象，需求是把obj2中的每个价格和obj1里面的一一合并成一个对象，最后生成一个新的数组，是这种形式

[{
  "id": 980550455852,
  "model": "XQG70-S1208FW",
  "color": "白",
  "invStatusName": "正品",
  "bactualQty": 10947,
  "brealyQty": 11000,
  "bavailQty": 53,
  "price": "6666"
}, {
  "id": 980550566221,
  "model": "XQB70-C3006",
  "color": "灰",
  "invStatusName": "正品",
  "bactualQty": 11,
  "brealyQty": 6,
  "bavailQty": -5,
  "price": "8888"
}]

解决办法：

合并数组或者对象在数组或对象前面加...，是es6的新写法，然后数组的map方法会返回数组.

var obj1 = [{
  "id": 980550455852,
  "model": "XQG70-S1208FW",
  "color": "白",
  "invStatusName": "正品",
  "bactualQty": 10947,
  "brealyQty": 11000,
  "bavailQty": 53
}, {
  "id": 980550566221,
  "model": "XQB70-C3006",
  "color": "灰",
  "invStatusName": "正品",
  "bactualQty": 11,
  "brealyQty": 6,
  "bavailQty": -5
}];

var obj2 = [{
  "price": "6666"
}, {
  "price": "8888"
}];
var obj = obj1.map((item,index) => {
    return {...item, ...obj2[index]};
});
console.log(obj);