oracle查询取第二名的值。
查询语句如下：
select ADD_SHI , sum(pro_zijin) as hzijin5 from ts_zijin where PRO_YEAr = 2013 group by ADD_SHI order by hzijin5 desc ;
查询结果为：
使用 rank 查询的写法如下：
select * from ( select a.*, rank() over(order by hzijin5 desc ) as lev
from ( select ADD_SHI , sum(pro_zijin) as hzijin5 from ts_zijin
where PRO_YEAr = 2013 group by ADD_SHI order by hzijin5
) a )where lev = 2 ;
查询结果如下：
rank的缺点在于，当两条数据并列第一名是，第二名取值则为null。展示如下：
所以使用 ROWNUM 比较好，写法如下：
SELECT * FROM ( SELECT A.*, ROWNUM RN FROM (
select sum(pro_zijin) as hzijin0 from ts_zijin where PRO_YEAr = 2015 group by ADD_SHI order by hzijin0 desc
) A ) ;