Codeup1928 日期处理

题目

code

#include <iostream>
#include <algorithm>
#include <cstring>
#include <cmath>
using namespace std;
int isLeap(int year){
    if(((year%4==0)&&(year%100!=0))||(year%400==0)){
        return 1;
    }
    else return 0;
}
int main(){
    int y1,y2,m1,m2,d1,d2,time1,time2;
    int month[13][2]={{0,0},{31,31},{28,29},{31,31},{30,30},{31,31},{30,30},{31,31},{31,31},{30,30},{31,31},{30,30},{31,31}};
    while(scanf("%d%d",&time1,&time2)!=EOF){
        // 初始化 让time1 比time2 小
        if(time1>time2){
            int temp=time1;
            time1=time2;
            time2=temp;
        }
        y1=time1/100000;
        y2=time2/100000;
        m1=time1%100000/100;
        m2=time2%100000/100;
        d1=time1%100;
        d2=time2%100;
        int ans=1;
        while(y1<y2||d1<d2||m1<m2){
            d1++;
            if(d1==month[m1][isLeap(y1)]+1){
                m1++;
                d1=1;
            }
            if(m1==13){
                y1++;
                m1=1;
            }
            ans++;
        }
        printf("%d\n",ans);
    }
    return 0;
}

总结

1. if(((year%40)&&(year%100!=0))||(year%4000) 来判断闰年
2. 先 if（time1>time2） 让time1 是较小的值！—》初始化
3.