CCF 2017-9-1 打酱油 python实现

 

n=input()
n=eval(n)
battle=n/10
def count(a):
    if 2*(a//5)+a%5//3>=a//3:
        return 2*(a//5)+a%5//3
    else:
        return a//3

count=battle+count(battle)
print('{:.0f}'.format(count))