1082 Read Number in Chinese （25 point(s)）

题解

本题测试数据比较寻常。 

#include<iostream>
#include<cstdio>
using namespace std;
string digit[10] = {"ling", "yi", "er", "san", "si", "wu", "liu", "qi", "ba", "jiu"};
string bit[10] = {"", "Shi", "Bai", "Qian", "Wan", "Shi", "Bai", "Qian", "Yi"};
string t;
int main() {
	cin >> t;
	int i;
	for(i = 0; i < t.length() - 1; ++i) {
		if(t[i] == '-') {
			cout << "Fu";
			continue;
		}
		if(t[i] == '0') {
			if(t.length() - i == 5 && (t.length() < 9 || t[i - 1] + t[i - 2] + t[i - 3] > 3 * '0')) {  //在万位 
				cout << " " << "Wan"; // 十万、百万、千万 
			} else if(t[i + 1] != '0'){
				cout << " " << "ling";
			} 
		} else {
			if(i) cout << " ";
			cout << digit[t[i] - '0'] << " " << bit[t.length() - 1 - i];
		}
	} 
	if(t[i] != '0') cout << " " << digit[t[i] - '0'];
	else if(t.length() == 1 && t[0] == '0') cout << "ling"; // case:0
	return 0;
}