python中闭包

 

def count():
    fs = []
    for i in range(1, 4):
        def f(j):
            def g():
                return j*j
            return g
        r = f(i)
        fs.append(r)
    return fs
f1, f2, f3 = count()
print (f1(), f2(), f3())

#运行结果
# 1  4   9

转自：廖雪峰