A经过初等行变换得到B A经过初等列变换得到B A经过初等行、列变换得到B inverse [010100001]−1=[010100001] \left[ \begin{matrix} 0 & 1 & 0 \\ 1 & 0 & 0 \\ 0 & 0 & 1 \end{matrix} \right]^{-1}= \left[ \begin{matrix} 0 & 1 & 0 \\ 1 & 0 & 0 \\ 0 & 0 & 1 \end{matrix} \right] ⎣⎡010100001⎦⎤−1=⎣⎡010100001⎦⎤ [100020001]−1=[1000120001] \left[ \begin{matrix} 1 & 0 & 0 \\ 0 & 2 & 0 \\ 0 & 0 & 1 \end{matrix} \right]^{-1}= \left[ \begin{matrix} 1 & 0 & 0 \\ 0 & \frac{1}{2} & 0 \\ 0 & 0 & 1 \end{matrix} \right] ⎣⎡100020001⎦⎤−1=⎣⎡1000210001⎦⎤ [100210001]−1=[100−210001] \left[ \begin{matrix} 1 & 0 & 0 \\ 2 & 1 & 0 \\ 0 & 0 & 1 \end{matrix} \right]^{-1}= \left[ \begin{matrix} 1 & 0 & 0 \\ -2 & 1 & 0 \\ 0 & 0 & 1 \end{matrix} \right] ⎣⎡120010001⎦⎤−1=⎣⎡1−20010001⎦⎤ 相关文章: