'''
搓螺旋丸，先从最外围填数，一圈隔一圈往内填
假设左基准点位置，r_base,c_base row col
'''
import numpy as np
def spiralize(number):
cur_len = number
r_base = 0
c_base = 0
map_arr = np.full((number,number),0)
times = number//2
print(times)
try:
while times:
#先赋值最外围的3边
for i in range(3):
temp_arr = map_arr[r_base : r_base+cur_len, c_base : c_base+cur_len]
if number%2 == 0 and cur_len <= 3 and r_base+cur_len < number and c_base+cur_len < number :
if temp_arr[cur_len-1,cur_len-1] == 1:
#temp_arr[cur_len-1,cur_len-1] = 3
map_arr = np.rot90(map_arr,-i)
return print('====\n',map_arr)
if(number == 2 and i == 2):
map_arr = np.rot90(map_arr,-i)
return print('====\n',map_arr)
temp_arr[0] = [1 for i in range(len(temp_arr[0]))]
map_arr = np.rot90(map_arr)
temp_arr = map_arr[r_base : r_base+1 , c_base : c_base + cur_len - 2]
temp_arr[0] = [1 for i in range(len(temp_arr[0]))]
map_arr = np.rot90(map_arr,-3)
r_base += 2
c_base += 2
cur_len -= 4
if r_base+1 <number and map_arr[r_base+1,c_base-1] != 1:
map_arr[r_base,c_base-1] = '1'
times -= 1
except IndexError:
return print('最终 map_arr = \n',map_arr)
spiralize(20)