描述
分析
1.暴力求解法:
class Solution {
public:
int getMaxLen(string s, int st)
{
int len = 0, length = s.length();
for(int i = st;i < length;i++)
{
int flag = 1;
for(int j = st;j < i;j++)
if(s[j] == s[i]){flag = 0;break;}
if(!flag)
break;
len++;
}
return len;
}
int lengthOfLongestSubstring(string s)
{
int length = s.length();
int maxlen = 0;
for(int i = 0;i < length;i++)
{
int t = getMaxLen(s, i);
maxlen = t > maxlen ? t : maxlen;
}
return maxlen;
}
};