进制数转换C语言实现

十进制转二进制

//十进制转二进制C语言实现
#include <stdio.h>

int Transformation(int num)
{
	int result = 0,n = 1,i,temp;
	temp = num;
	while(temp)
	{
		i = temp % 2;
		result = n * i + result;
		n *= 10;
		temp = temp / 2;
	}
	return result;
}

int main(void)
{
	int num,result;
	printf("请输入一个十进制数：");
	scanf("%d",&num);
	result = Transformation(num);
	printf("%d的二进制数为0B%d\n",num,result);
}

 

二进制转十进制

#include <stdio.h>
#include <stdlib.h>
#include <string.h>
 
int main()
{
    char a[17];
    printf("请输入一个二进制数:0B");
    gets(a);
    int len,i,sum = 0,m,j;
    len = strlen(a);
    if(len <= 16)
    {
        for(i = 0;i < len;i++)
    {
        m=1;
        if(a[i] == '1')
        {
            for(j = 1;j <= len - i - 1;j++)
                m *= 2;
            sum += m;
        }
    }
    printf("十进制数为：%d\n",sum);
    }
    return 0;
}