leetcode       401. Binary Watch          

A binary watch has 4 LEDs on the top which represent the hours (0-11), and the 6 LEDs on the bottom represent the minutes (0-59).

Each LED represents a zero or one, with the least significant bit on the right.

Easy-44

For example, the above binary watch reads "3:25".

Given a non-negative integer n which represents the number of LEDs that are currently on, return all possible times the watch could represent.

Example:

Input: n = 1
Return: ["1:00", "2:00", "4:00", "8:00", "0:01", "0:02", "0:04", "0:08", "0:16", "0:32"]

Note:

  • The order of output does not matter.
  • The hour must not contain a leading zero, for example "01:00" is not valid, it should be "1:00".
  • The minute must be consist of two digits and may contain a leading zero, for example "10:2" is not valid, it should be "10:02".

AC:

/**
 * Return an array of size *returnSize.
 * Note: The returned array must be malloced, assume caller calls free().
 */
int countOne(int k)
{
    int len=0;
    while(k>0)
    {
        if(k%2==1)
        {
            len++;
        }
        k=k/2;
    }
    return len;
}
char** readBinaryWatch(int num, int* returnSize) {
    int h,m,len=0;
    char** result=(char**)malloc(12*60*sizeof(char*));
    for(h=0;h<12;h++)
    {
        for(m=0;m<60;m++)
        {
            if(countOne(h*64+m)==num)
            {
                result[len]=(char*)malloc(6*sizeof(char));
                char buf[6];
                sprintf(buf,"%d",h);
                strcat(result[len],buf);
                strcat(result[len],":");
                if(m/10==0)
                {
                    strcat(result[len],"0");
                }
                sprintf(buf,"%d",m);
                strcat(result[len],buf);
                len++;
            }
        }
    }
    *returnSize=len;
    return result;
}

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