445. Add Two Numbers II

题目

我的代码（打败了99.6%）

简单来说就是先将list转化为int，然后计算，然后再转换为int。

# Definition for singly-linked list.
# class ListNode:
#     def __init__(self, x):
#         self.val = x
#         self.next = None

class Solution:
    def addTwoNumbers(self, l1: ListNode, l2: ListNode) -> ListNode:
        val1=0
        while l1:
            val1*=10
            val1+=l1.val
            l1=l1.next
        val2=0
        while l2:
            val2*=10
            val2+=l2.val
            l2=l2.next
        val3=val1+val2
        if val3==0:
            return ListNode(0)
        tail=None
        while val3>0:
            new=ListNode(val3%10)
            new.next=tail
            tail=new
            val3=val3//10
        return new