【发布时间】:2016-09-27 20:17:34
【问题描述】:
我刚开始编写 Android 代码,但我仍在从错误中吸取教训。我使用WebView 加载内部html 页面,我想通过单击webview 上的超链接打开另一个活动窗口,该窗口将是barcode scanner。但是我收到此错误
Unable to open asset URL: file:///android_asset/activity_a://qrcodeactivity
AndroidManifest.xml
<activity android:name="qrcodeactivity" >
<intent-filter>
<category android:name="android.intent.category.DEFAULT" />
<action android:name="android.intent.action.VIEW" />
<data android:scheme="activity_a" />
</intent-filter>
</activity>
index.html
<a href="activity_a://qrcodeactivity">Activity A</a>
MyWebClient Java
private class MyWebViewClient extends WebViewClient {
@Override
public boolean shouldOverrideUrlLoading(WebView view, String url) {
if (url.equals("activity_a://qrcodeactivity")) {
Intent intent = new Intent(getContext(), qrcodeactivity.class);
startActivity(intent);
return true; // Handle By application itself
} else {
view.loadUrl(url);
if (loader.equals("pull")) {
swipeContainer.setRefreshing(true);
} else if (loader.equals("dialog")) {
if (!pd.isShowing()) {
pd.show();
}
} else if (loader.equals("never")) {
Log.d("WebView", "No Loader selected");
}
return true;
}
}
@Override
public void onPageFinished(WebView view, String url) {
if (pd.isShowing()) {
pd.dismiss();
}
if (swipeContainer.isRefreshing()) {
swipeContainer.setRefreshing(false);
}
}
@Override
public void onReceivedError(WebView view, int errorCode, String description, String failingUrl) {
webView.loadUrl("file:///android_asset/" + getString(R.string.error_page));
}
}
【问题讨论】:
标签: android