如何在不使用 Python 库的情况下从单行输入制作矩阵？

Question

我需要制作一个大小为 M*M（这是用户输入值）的方阵，然后，我应该用一行空格分隔的数字制作一个矩阵。

sizeOfMatrix = int(input())
matrix_input = input()
matrix = [[]*3]*3
for i in range(sizeOfMatrix):
    for j in range (sizeOfMatrix):
    # And this is where I got stuck
        matrix[i][j].append()

Answer 1

您可以试试这个 - 它遵循原始 PO，但不需要两个循环。 [注意] 它基于 PO 指示的示例输入 - 将 matrix_input (numbers) 收集在一行中（如问题标题所述）。

size  = int(input('Enter the size of this Square Matrix: '))  # eg. 3; R == C
numbers = list(map(int, input(f' Enter {size*size} numbers: ').split()))  # all 3x3 numbers 

matrix = []        # [[]*3]*3

for i in range(0, len(numbers), size):
    matrix.append(numbers[i: i+size]) 

print(matrix)

交互运行和输出：

Enter the size of this Square Matrix: 3
Enter 9 numbers: 1 2 3 4 5 6 7 8 9
[[1, 2, 3], [4, 5, 6], [7, 8, 9]]

或者为这个方阵搭配更漂亮的单行：

M = []
while not M or len(M) < len(M[0]):
    M.append(list(map(int,  input('Enter the number for a row: ').split())))

跑步：

Enter the number for a row: 1 2 3
Enter the number for a row: 4 5 6
Enter the number for a row: 7 8 9
>>> M
[[1, 2, 3], [4, 5, 6], [7, 8, 9]]

Answer 2

如果你想要方阵使 R=C

R = int(input("Enter the number of rows:")) 
C = int(input("Enter the number of columns:")) 
  
# Initialize matrix 
matrix = [] 
print("Enter the entries rowwise:") 
  
# For user input 
for i in range(R):          # A for loop for row entries 
    a =[] 
    for j in range(C):      # A for loop for column entries 
         a.append(int(input())) 
    matrix.append(a) 

用于打印矩阵

for i in range(R): 
    for j in range(C): 
        print(matrix[i][j], end = " ") 
    print() 

Answer 3

这就是创建方阵的方式。

sizeOfMatrix = int(input('Matrix Size: '))
mat = []

for i in range(sizeOfMatrix):
    rows = list(map(int, input('Enter space separated values: ').split()))[:sizeOfMatrix]
    mat.append(rows)

print(f'\nMatrix:')
for i in mat:
    print(*i)

Matrix Size: 3
Enter space separated values: 2 1 6
Enter space separated values: 0 21 8
Enter space separated values: 6 9 7

Matrix:
2 1 6
0 21 8
6 9 7