启动特定的故事板答案

【问题标题】：Launch specific Storyboard启动特定的故事板
【发布时间】：2019-05-05 23:38:34
【问题描述】：

如果设备是 iPhone 5，我需要启动一个特定的故事板，如果设备是 iPhone 4S 或更早版本，我需要启动另一个故事板。我知道我需要添加一些代码来执行 didFinishLaunchingWithOptions 方法，但我不知道具体是哪个！

谁能给我正确的代码？

【问题讨论】：

标签： storyboard

【解决方案1】：

这个问题有一个很好的解决方案：

xcode 4.5 how to pick storyboards at launch

基本上，您可以在 didFinishLaunchingWithOptions 中检查屏幕高度并加载相应的记分牌。

【讨论】：

【解决方案2】：

您必须定义两个不同的故事板。一种用于 iPhone 4 尺寸，一种用于 iPhone 5 尺寸。

然后将以下代码添加到您的应用程序委托应用程序的 didFinishLaunchingWithOptions 方法中...

// Override point for customization after application launch.
CGSize iOSDeviceScreenSize = [[UIScreen mainScreen] bounds].size;

if (iOSDeviceScreenSize.height == 480)
{
    // Instantiate a new storyboard object using the storyboard file named Storyboard_iPhone35
    UIStoryboard *iPhone35Storyboard = [UIStoryboard storyboardWithName:@"iPhone4" bundle:nil];

    // Instantiate the initial view controller object from the storyboard
    UIViewController *initialViewController = [iPhone35Storyboard instantiateInitialViewController];

    // Instantiate a UIWindow object and initialize it with the screen size of the iOS device
    self.window = [[UIWindow alloc] initWithFrame:[[UIScreen mainScreen] bounds]];

    // Set the initial view controller to be the root view controller of the window object
    self.window.rootViewController  = initialViewController;

    // Set the window object to be the key window and show it
    [self.window makeKeyAndVisible];
}

if (iOSDeviceScreenSize.height == 568)
{   // iPhone 5 and iPod Touch 5th generation: 4 inch screen
    // Instantiate a new storyboard object using the storyboard file named Storyboard_iPhone4
    UIStoryboard *iPhone4Storyboard = [UIStoryboard storyboardWithName:@"iPhone5" bundle:nil];

    UIViewController *initialViewController = [iPhone4Storyboard instantiateInitialViewController];
    self.window = [[UIWindow alloc] initWithFrame:[[UIScreen mainScreen] bounds]];
    self.window.rootViewController  = initialViewController;
    [self.window makeKeyAndVisible];
}
return YES;

或者您可以随时尝试使用自动布局来碰碰运气。无论哪种方式都有效。

【讨论】：

【解决方案3】：

您可以检查 iPhone 4/iPhone 5 并根据它实例化故事板

以下代码甚至可以告诉您 iPhone 或 iPad。

可以在整个应用程序中全局保存 iPhone 或 iPad bool。

注意：默认情况下 iphone4 故事板将被实例化。

- (BOOL)application:(UIApplication *)application didFinishLaunchingWithOptions:(NSDictionary *)launchOptions{


iPhone5 = NO;
iPad = NO;

// Override point for customization after application launch.
UIStoryboard *storyBoard;

if(UI_USER_INTERFACE_IDIOM() == UIUserInterfaceIdiomPhone)
{
    if ([UIScreen mainScreen].scale == 2.0f)
    {
        CGSize result = [[UIScreen mainScreen] bounds].size;
        CGFloat scale = [UIScreen mainScreen].scale;
        result = CGSizeMake(result.width * scale, result.height * scale);

        if(result.height == 960)
        {
            iPhone5 = NO;
           // NSLog(@"iPhone 4, 4s Retina Resolution");
        }
        if(result.height == 1136)
        {
            iPhone5 = YES;
          //  NSLog(@"iPhone 5 Resolution");
            storyBoard = [UIStoryboard storyboardWithName:@"Storyboard" bundle:nil];
            UIViewController *tabBarController = [storyBoard instantiateInitialViewController];
            self.window.rootViewController = tabBarController ;
        }
    }
    else
    {
      //  NSLog(@"iPhone Standard Resolution");
        iPad = YES;
    }
}
else
{
    iPad = YES;
}

return YES;

}

【讨论】：